The *equations* are generally stated in words and it is for this reason we refer to these *problems* as word *problems*. If the two parts are in the ratio 5 : 3, find the number and the two parts. *With* the help of *equations* in one variable, we have already practiced *equations* to solve some real life *problems*. Solution: Let one part of the number be x Then the other part of the number = x 10The ratio of the two numbers is 5 : 3Therefore, (x 10)/x = 5/3⇒ 3(x 10) = 5x ⇒ 3x 30 = 5x⇒ 30 = 5x - 3x⇒ 30 = 2x ⇒ x = 30/2 ⇒ x = 15Therefore, x 10 = 15 10 = 25Therefore, the number = 25 15 = 40 The two parts are 15 and 25. Then Robert’s father’s age = 4x After 5 *years*, Robert’s age = x 5Father’s age = 4x 5According to the question, 4x 5 = 3(x 5) ⇒ 4x 5 = 3x 15 ⇒ 4x - 3x = 15 - 5 ⇒ x = 10⇒ 4x = 4 × 10 = 40 Robert’s present age is 10 *years* and that of his father’s age = 40 *years*. Here's how you'd fure out his age for class:stand for my age in 2009.

## Solving problems with equations year 9

Worked-out word __problems__ on linear __equations__ __with__ solutions explained step-by-step in different types of examples. Solution: Then the other number = x 9Let the number be x. Therefore, x 4 = 2(x - 5 4) ⇒ x 4 = 2(x - 1) ⇒ x 4 = 2x - 2⇒ x 4 = 2x - 2⇒ x - 2x = -2 - 4⇒ -x = -6⇒ x = 6Therefore, Aaron’s present age = x - 5 = 6 - 5 = 1Therefore, present age of Ron = 6 __years__ and present age of Aaron = 1 __year__.5. Then the other multiple of 5 will be x 5 and their sum = 55Therefore, x x 5 = 55⇒ 2x 5 = 55⇒ 2x = 55 - 5⇒ 2x = 50⇒ x = 50/2 ⇒ x = 25 Therefore, the multiples of 5, i.e., x 5 = 25 5 = 30Therefore, the two consecutive multiples of 5 whose sum is 55 are 25 and 30. The difference in the measures of two complementary angles is 12°. ⇒ 3x/5 - x/2 = 4⇒ (6x - 5x)/10 = 4⇒ x/10 = 4⇒ x = 40The required number is 40. From Chapter 1: The Distributive Law, Exercise 7: Binomial Expansions.

Using symbols instead of numbers makes it possible for work in a general rather than a specific way, and it allows us to manipulate and rewrite the relationships between quantities in different ways. Hh school math students can use these algebra

problemsfor study purposes.

### Solving problems with equations year 9

#### Solving problems with equations year 9

The suggested collection of mathematical folklore mht be enjoyable for mathematicians and for students because every joke contains a portion of truth or lie about our profession. We value excellent academic writing and strive to provide outstanding essay writing services each and every time you place an order.

Elementary Algebra is about manipulating mathematical expressions, **with** quantities represented by symbols e.g x, y or z. HOW TO WRITE IN DIFFERENT LANGUAGES ON IPHONE From Chapter 3: Pythagoras' Theorem, Exercise 15: Navation __Problems__.

Solving problems with equations year 9:

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